315040131103 has 8 divisors (see below), whose sum is σ = 319824957872. Its totient is φ = 310257737856.

The previous prime is 315040131067. The next prime is 315040131149. The reversal of 315040131103 is 301131040513.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 315040131103 - 2¹³ = 315040122911 is a prime.

It is a super-3 number, since 3×315040131103³ (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (315040132103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 346650 + ... + 866167.

It is an arithmetic number, because the mean of its divisors is an integer number (39978119734).

Almost surely, 2^315040131103 is an apocalyptic number.

315040131103 is a deficient number, since it is larger than the sum of its proper divisors (4784826769).

315040131103 is a wasteful number, since it uses less digits than its factorization.

315040131103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1216761.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 315040131103 its reverse (301131040513), we get a palindrome (616171171616).

The spelling of 315040131103 in words is "three hundred fifteen billion, forty million, one hundred thirty-one thousand, one hundred three".