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315064503401 = 912913451211
BaseRepresentation
bin1001001010110110100…
…11101100110001101001
31010010020101110002110112
410211123103230301221
520130223003102101
6400423313424105
731522410043334
oct4453323546151
91103211402415
10315064503401
1111168877570a
125108a56b035
1323930b4064b
141136bb5761b
1582deeb56bb
hex495b4ecc69

315064503401 has 4 divisors (see below), whose sum is σ = 315068045904. Its totient is φ = 315060960900.

The previous prime is 315064503389. The next prime is 315064503419. The reversal of 315064503401 is 104305460513.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-315064503401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (315064503101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1634315 + ... + 1816896.

It is an arithmetic number, because the mean of its divisors is an integer number (78767011476).

Almost surely, 2315064503401 is an apocalyptic number.

It is an amenable number.

315064503401 is a deficient number, since it is larger than the sum of its proper divisors (3542503).

315064503401 is an equidigital number, since it uses as much as digits as its factorization.

315064503401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3542502.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 315064503401 its reverse (104305460513), we get a palindrome (419369963914).

The spelling of 315064503401 in words is "three hundred fifteen billion, sixty-four million, five hundred three thousand, four hundred one".

Divisors: 1 91291 3451211 315064503401