Base | Representation |
---|---|
bin | 1110010101000101110110… |
… | …10101101010001000001001 |
3 | 11010120102110101020102021101 |
4 | 13022202323111222020021 |
5 | 13112234033403203200 |
6 | 151003544132141401 |
7 | 6431411346001621 |
oct | 712427325521011 |
9 | 133512411212241 |
10 | 31511023100425 |
11 | a04982805a9a0 |
12 | 364b069a67861 |
13 | 14776274aa88b |
14 | 7ad1da9bb881 |
15 | 399a19c7726a |
hex | 1ca8bb56a209 |
31511023100425 has 12 divisors (see below), whose sum is σ = 42625820339856. Its totient is φ = 22917107709200.
The previous prime is 31511023100413. The next prime is 31511023100471. The reversal of 31511023100425 is 52400132011513.
It is not a de Polignac number, because 31511023100425 - 211 = 31511023098377 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31511023100393 and 31511023100402.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 57292768999 + ... + 57292769548.
It is an arithmetic number, because the mean of its divisors is an integer number (3552151694988).
Almost surely, 231511023100425 is an apocalyptic number.
It is an amenable number.
31511023100425 is a deficient number, since it is larger than the sum of its proper divisors (11114797239431).
31511023100425 is a wasteful number, since it uses less digits than its factorization.
31511023100425 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 114585538568 (or 114585538563 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 31511023100425 its reverse (52400132011513), we get a palindrome (83911155111938).
The spelling of 31511023100425 in words is "thirty-one trillion, five hundred eleven billion, twenty-three million, one hundred thousand, four hundred twenty-five".
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