Base | Representation |
---|---|
bin | 11101010110001101… |
… | …101111000001101101 |
3 | 10000100001220102201011 |
4 | 131112031233001231 |
5 | 1004013332242031 |
6 | 22250454345221 |
7 | 2163606612103 |
oct | 352615570155 |
9 | 100301812634 |
10 | 31511212141 |
11 | 12400292092 |
12 | 613505b211 |
13 | 2c824b1876 |
14 | 174d029c73 |
15 | c4663a6b1 |
hex | 75636f06d |
31511212141 has 4 divisors (see below), whose sum is σ = 32244031072. Its totient is φ = 30778393212.
The previous prime is 31511212079. The next prime is 31511212147. The reversal of 31511212141 is 14121211513.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 31511212141 - 29 = 31511211629 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31511212147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 366409401 + ... + 366409486.
It is an arithmetic number, because the mean of its divisors is an integer number (8061007768).
Almost surely, 231511212141 is an apocalyptic number.
It is an amenable number.
31511212141 is a deficient number, since it is larger than the sum of its proper divisors (732818931).
31511212141 is an equidigital number, since it uses as much as digits as its factorization.
31511212141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 732818930.
The product of its digits is 240, while the sum is 22.
Adding to 31511212141 its reverse (14121211513), we get a palindrome (45632423654).
The spelling of 31511212141 in words is "thirty-one billion, five hundred eleven million, two hundred twelve thousand, one hundred forty-one".
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