Search a number
-
+
315121011 = 3105040337
BaseRepresentation
bin10010110010000…
…101110101110011
3210221221210202120
4102302011311303
51121132333021
651134045323
710544325102
oct2262056563
9727853676
10315121011
11151972097
1289649843
135039354a
142dbcc039
151c9e92c6
hex12c85d73

315121011 has 4 divisors (see below), whose sum is σ = 420161352. Its totient is φ = 210080672.

The previous prime is 315121007. The next prime is 315121013. The reversal of 315121011 is 110121513.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110121513 = 336707171.

It is a cyclic number.

It is not a de Polignac number, because 315121011 - 22 = 315121007 is a prime.

It is not an unprimeable number, because it can be changed into a prime (315121013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52520166 + ... + 52520171.

It is an arithmetic number, because the mean of its divisors is an integer number (105040338).

Almost surely, 2315121011 is an apocalyptic number.

315121011 is a deficient number, since it is larger than the sum of its proper divisors (105040341).

315121011 is a wasteful number, since it uses less digits than its factorization.

315121011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105040340.

The product of its (nonzero) digits is 30, while the sum is 15.

The square root of 315121011 is about 17751.6481206676. The cubic root of 315121011 is about 680.4963295401.

Adding to 315121011 its reverse (110121513), we get a palindrome (425242524).

It can be divided in two parts, 31512 and 1011, that added together give a palindrome (32523).

The spelling of 315121011 in words is "three hundred fifteen million, one hundred twenty-one thousand, eleven".

Divisors: 1 3 105040337 315121011