Base | Representation |
---|---|
bin | 101101110110110011000… |
… | …100011000110111010111 |
3 | 102011020211121112102120211 |
4 | 231312303010120313113 |
5 | 403112142104100210 |
6 | 10411352012110251 |
7 | 443445024046144 |
oct | 55666304306727 |
9 | 12136747472524 |
10 | 3151215300055 |
11 | 1005471980839 |
12 | 42a887765387 |
13 | 19b209acc904 |
14 | ac73bc3b3cb |
15 | 56e84d8238a |
hex | 2ddb3118dd7 |
3151215300055 has 12 divisors (see below), whose sum is σ = 3990957440472. Its totient is φ = 2388289489200.
The previous prime is 3151215300041. The next prime is 3151215300073. The reversal of 3151215300055 is 5500035121513.
It is not a de Polignac number, because 3151215300055 - 227 = 3151081082327 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 872911021 + ... + 872914630.
It is an arithmetic number, because the mean of its divisors is an integer number (332579786706).
Almost surely, 23151215300055 is an apocalyptic number.
3151215300055 is a deficient number, since it is larger than the sum of its proper divisors (839742140417).
3151215300055 is a wasteful number, since it uses less digits than its factorization.
3151215300055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1745825694 (or 1745825675 counting only the distinct ones).
The product of its (nonzero) digits is 11250, while the sum is 31.
The spelling of 3151215300055 in words is "three trillion, one hundred fifty-one billion, two hundred fifteen million, three hundred thousand, fifty-five".
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