Base | Representation |
---|---|
bin | 101101110111000001000… |
… | …101110000110111001001 |
3 | 102011021110000011221012102 |
4 | 231313001011300313021 |
5 | 403113132314312023 |
6 | 10411431214123145 |
7 | 443453611422251 |
oct | 55670105606711 |
9 | 12137400157172 |
10 | 3151450541513 |
11 | 100558274416a |
12 | 42a9324b04b5 |
13 | 19b246775841 |
14 | ac761194961 |
15 | 56e9a84d628 |
hex | 2ddc1170dc9 |
3151450541513 has 16 divisors (see below), whose sum is σ = 3173600923200. Its totient is φ = 3129354233280.
The previous prime is 3151450541479. The next prime is 3151450541531.
3151450541513 is nontrivially palindromic in base 10.
3151450541513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 3151450541513 - 232 = 3147155574217 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3151450547513) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 473116403 + ... + 473123063.
It is an arithmetic number, because the mean of its divisors is an integer number (198350057700).
Almost surely, 23151450541513 is an apocalyptic number.
It is an amenable number.
3151450541513 is a deficient number, since it is larger than the sum of its proper divisors (22150381687).
3151450541513 is a wasteful number, since it uses less digits than its factorization.
3151450541513 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10232.
The product of its (nonzero) digits is 90000, while the sum is 38.
It can be divided in two parts, 3151450 and 541513, that added together give a palindrome (3692963).
The spelling of 3151450541513 in words is "three trillion, one hundred fifty-one billion, four hundred fifty million, five hundred forty-one thousand, five hundred thirteen".
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