Base | Representation |
---|---|
bin | 1001001011000000110… |
… | …11100001111001010111 |
3 | 1010010110101011020011020 |
4 | 10211200123201321113 |
5 | 20130412003121241 |
6 | 400440023412223 |
7 | 31524502362363 |
oct | 4454033417127 |
9 | 1103411136136 |
10 | 315150442071 |
11 | 111722232703 |
12 | 510b32b4073 |
13 | 2394589cb2a |
14 | 113793282a3 |
15 | 82e77ddb66 |
hex | 49606e1e57 |
315150442071 has 4 divisors (see below), whose sum is σ = 420200589432. Its totient is φ = 210100294712.
The previous prime is 315150442069. The next prime is 315150442081. The reversal of 315150442071 is 170244051513.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 315150442071 - 21 = 315150442069 is a prime.
It is a super-2 number, since 2×3151504420712 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (315150442081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52525073676 + ... + 52525073681.
It is an arithmetic number, because the mean of its divisors is an integer number (105050147358).
Almost surely, 2315150442071 is an apocalyptic number.
315150442071 is a deficient number, since it is larger than the sum of its proper divisors (105050147361).
315150442071 is a wasteful number, since it uses less digits than its factorization.
315150442071 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105050147360.
The product of its (nonzero) digits is 16800, while the sum is 33.
Adding to 315150442071 its reverse (170244051513), we get a palindrome (485394493584).
The spelling of 315150442071 in words is "three hundred fifteen billion, one hundred fifty million, four hundred forty-two thousand, seventy-one".
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