Base | Representation |
---|---|
bin | 11101010110101111… |
… | …011011010000010111 |
3 | 10000100200112010211002 |
4 | 131112233123100113 |
5 | 1004023112402210 |
6 | 22251411533515 |
7 | 2164044645113 |
oct | 352657332027 |
9 | 100320463732 |
10 | 31520044055 |
11 | 12405274695 |
12 | 6137bba29b |
13 | 2c84284856 |
14 | 1750288743 |
15 | c472d24a5 |
hex | 756bdb417 |
31520044055 has 4 divisors (see below), whose sum is σ = 37824052872. Its totient is φ = 25216035240.
The previous prime is 31520044051. The next prime is 31520044067. The reversal of 31520044055 is 55044002513.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 31520044055 - 22 = 31520044051 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31520044051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3152004401 + ... + 3152004410.
It is an arithmetic number, because the mean of its divisors is an integer number (9456013218).
Almost surely, 231520044055 is an apocalyptic number.
31520044055 is a deficient number, since it is larger than the sum of its proper divisors (6304008817).
31520044055 is an equidigital number, since it uses as much as digits as its factorization.
31520044055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6304008816.
The product of its (nonzero) digits is 12000, while the sum is 29.
Adding to 31520044055 its reverse (55044002513), we get a palindrome (86564046568).
The spelling of 31520044055 in words is "thirty-one billion, five hundred twenty million, forty-four thousand, fifty-five".
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