Base | Representation |
---|---|
bin | 100011110101100100001100… |
… | …0110001110000101001100101 |
3 | 1112100010020110100021212112120 |
4 | 1013223020120301300221211 |
5 | 312304122300311421013 |
6 | 3034232251212540153 |
7 | 123253162304313516 |
oct | 10753103061605145 |
9 | 1470106410255476 |
10 | 315225245420133 |
11 | 91493304152a84 |
12 | 2b430920a81659 |
13 | 106b77c7c77b89 |
14 | 57badaa1bca0d |
15 | 2669aea947123 |
hex | 11eb218c70a65 |
315225245420133 has 8 divisors (see below), whose sum is σ = 420300518421696. Its totient is φ = 210150068016000.
The previous prime is 315225245420131. The next prime is 315225245420149. The reversal of 315225245420133 is 331024542522513.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 315225245420133 - 21 = 315225245420131 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (315225245420131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15814668 + ... + 29674133.
It is an arithmetic number, because the mean of its divisors is an integer number (52537564802712).
Almost surely, 2315225245420133 is an apocalyptic number.
It is an amenable number.
315225245420133 is a deficient number, since it is larger than the sum of its proper divisors (105075273001563).
315225245420133 is a wasteful number, since it uses less digits than its factorization.
315225245420133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47798715.
The product of its (nonzero) digits is 864000, while the sum is 42.
Adding to 315225245420133 its reverse (331024542522513), we get a palindrome (646249787942646).
The spelling of 315225245420133 in words is "three hundred fifteen trillion, two hundred twenty-five billion, two hundred forty-five million, four hundred twenty thousand, one hundred thirty-three".
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