315240433 has 4 divisors (see below), whose sum is σ = 315557620. Its totient is φ = 314923248.

The previous prime is 315240383. The next prime is 315240437. The reversal of 315240433 is 334042513.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334042513 = 7 ⋅47720359.

It can be written as a sum of positive squares in 2 ways, for example, as 267257104 + 47983329 = 16348^2 + 6927^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-315240433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 315240398 and 315240407.

It is not an unprimeable number, because it can be changed into a prime (315240437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157098 + ... + 159091.

It is an arithmetic number, because the mean of its divisors is an integer number (78889405).

Almost surely, 2^315240433 is an apocalyptic number.

It is an amenable number.

315240433 is a deficient number, since it is larger than the sum of its proper divisors (317187).

315240433 is an equidigital number, since it uses as much as digits as its factorization.

315240433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 317186.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 315240433 is about 17755.0114897175. The cubic root of 315240433 is about 680.5822816729.

Adding to 315240433 its reverse (334042513), we get a palindrome (649282946).

The spelling of 315240433 in words is "three hundred fifteen million, two hundred forty thousand, four hundred thirty-three".