Base | Representation |
---|---|
bin | 100011110110110111001010… |
… | …0001101111001101110010010 |
3 | 1112100202021022221111000211001 |
4 | 1013231232110031321232102 |
5 | 312320032140433212114 |
6 | 3034450154251212214 |
7 | 123302100345601201 |
oct | 10755562415715622 |
9 | 1470667287430731 |
10 | 315403410054034 |
11 | 91551920475475 |
12 | 2b45b363a4706a |
13 | 106cb54c598a83 |
14 | 57c586c337238 |
15 | 266e576e5d374 |
hex | 11edb94379b92 |
315403410054034 has 4 divisors (see below), whose sum is σ = 473105115081054. Its totient is φ = 157701705027016.
The previous prime is 315403410054001. The next prime is 315403410054041. The reversal of 315403410054034 is 430450014304513.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 310595682875625 + 4807727178409 = 17623725^2 + 2192653^2 .
It is a super-2 number, since 2×3154034100540342 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 315403410053984 and 315403410054002.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78850852513507 + ... + 78850852513510.
Almost surely, 2315403410054034 is an apocalyptic number.
315403410054034 is a deficient number, since it is larger than the sum of its proper divisors (157701705027020).
315403410054034 is a wasteful number, since it uses less digits than its factorization.
315403410054034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 157701705027019.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 315403410054034 its reverse (430450014304513), we get a palindrome (745853424358547).
The spelling of 315403410054034 in words is "three hundred fifteen trillion, four hundred three billion, four hundred ten million, fifty-four thousand, thirty-four".
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