Base | Representation |
---|---|
bin | 1001001011100011011… |
… | …00101001101100011011 |
3 | 1010011012120021120022010 |
4 | 10211301230221230123 |
5 | 20132010134040011 |
6 | 400524453001003 |
7 | 31534620656031 |
oct | 4456154515433 |
9 | 1104176246263 |
10 | 315440143131 |
11 | 111860812373 |
12 | 51174323163 |
13 | 23990902c89 |
14 | 113a59ba551 |
15 | 8312e661a6 |
hex | 4971b29b1b |
315440143131 has 4 divisors (see below), whose sum is σ = 420586857512. Its totient is φ = 210293428752.
The previous prime is 315440143111. The next prime is 315440143133. The reversal of 315440143131 is 131341044513.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 315440143131 - 25 = 315440143099 is a prime.
It is a super-2 number, since 2×3154401431312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (315440143133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52573357186 + ... + 52573357191.
It is an arithmetic number, because the mean of its divisors is an integer number (105146714378).
Almost surely, 2315440143131 is an apocalyptic number.
315440143131 is a deficient number, since it is larger than the sum of its proper divisors (105146714381).
315440143131 is a wasteful number, since it uses less digits than its factorization.
315440143131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 105146714380.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 315440143131 its reverse (131341044513), we get a palindrome (446781187644).
The spelling of 315440143131 in words is "three hundred fifteen billion, four hundred forty million, one hundred forty-three thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •