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31544053141 = 73432110317
BaseRepresentation
bin11101011000001011…
…000000110110010101
310000102100200221002111
4131120023000312111
51004100234200031
622254030311021
72164456012336
oct353013006625
9100370627074
1031544053141
1112417883007
126144058471
132c8923ca03
14175353828d
15c494761b1
hex7582c0d95

31544053141 has 4 divisors (see below), whose sum is σ = 31976163532. Its totient is φ = 31111942752.

The previous prime is 31544053049. The next prime is 31544053187. The reversal of 31544053141 is 14135044513.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 22516202916 + 9027850225 = 150054^2 + 95015^2 .

It is a cyclic number.

It is not a de Polignac number, because 31544053141 - 211 = 31544051093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31544053241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216055086 + ... + 216055231.

It is an arithmetic number, because the mean of its divisors is an integer number (7994040883).

Almost surely, 231544053141 is an apocalyptic number.

It is an amenable number.

31544053141 is a deficient number, since it is larger than the sum of its proper divisors (432110391).

31544053141 is an equidigital number, since it uses as much as digits as its factorization.

31544053141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 432110390.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 31544053141 its reverse (14135044513), we get a palindrome (45679097654).

The spelling of 31544053141 in words is "thirty-one billion, five hundred forty-four million, fifty-three thousand, one hundred forty-one".

Divisors: 1 73 432110317 31544053141