315555100401141 has 28 divisors (see below), whose sum is σ = 474138070287168. Its totient is φ = 209915703714024.

The previous prime is 315555100401113. The next prime is 315555100401251. The reversal of 315555100401141 is 141104001555513.

315555100401141 is a `hidden beast` number, since 3 + 1 + 5 + 5 + 5 + 5 + 100 + 401 + 141 = 666.

It is not a de Polignac number, because 315555100401141 - 2⁶ = 315555100401077 is a prime.

It is a super-2 number, since 2×315555100401141² (a number of 30 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 315555100401096 and 315555100401105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (315555100401941) by changing a digit.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 467114115 + ... + 467789168.

It is an arithmetic number, because the mean of its divisors is an integer number (16933502510256).

Almost surely, 2^{315555100401141} is an apocalyptic number.

It is an amenable number.

315555100401141 is a deficient number, since it is larger than the sum of its proper divisors (158582969886027).

315555100401141 is an frugal number, since it uses more digits than its factorization.

315555100401141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 934903764 (or 934903749 counting only the distinct ones).

The product of its (nonzero) digits is 30000, while the sum is 36.

Adding to 315555100401141 its reverse (141104001555513), we get a palindrome (456659101956654).

The spelling of 315555100401141 in words is "three hundred fifteen trillion, five hundred fifty-five billion, one hundred million, four hundred one thousand, one hundred forty-one".