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316113301 = 745159043
BaseRepresentation
bin10010110101111…
…000000110010101
3211000211012221001
4102311320012111
51121411111201
651211223301
710555630060
oct2265700625
9730735831
10316113301
1115248a669
1289a47b31
13506500ba
142dda98d7
151cb43301
hex12d78195

316113301 has 4 divisors (see below), whose sum is σ = 361272352. Its totient is φ = 270954252.

The previous prime is 316113289. The next prime is 316113331. The reversal of 316113301 is 103311613.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 103311613 = 611693633.

It is a cyclic number.

It is not a de Polignac number, because 316113301 - 25 = 316113269 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (316113331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22579515 + ... + 22579528.

It is an arithmetic number, because the mean of its divisors is an integer number (90318088).

Almost surely, 2316113301 is an apocalyptic number.

It is an amenable number.

316113301 is a deficient number, since it is larger than the sum of its proper divisors (45159051).

316113301 is an equidigital number, since it uses as much as digits as its factorization.

316113301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45159050.

The product of its (nonzero) digits is 162, while the sum is 19.

The square root of 316113301 is about 17779.5753886306. The cubic root of 316113301 is about 681.2098566700.

Adding to 316113301 its reverse (103311613), we get a palindrome (419424914).

The spelling of 316113301 in words is "three hundred sixteen million, one hundred thirteen thousand, three hundred one".

Divisors: 1 7 45159043 316113301