Base | Representation |
---|---|
bin | 101110000000110100010… |
… | …100011011001001001001 |
3 | 102012021121101100201200101 |
4 | 232000310110123021021 |
5 | 403301210231333040 |
6 | 10420331330005401 |
7 | 444305440661152 |
oct | 56006424331111 |
9 | 12167541321611 |
10 | 3161973699145 |
11 | 1009a927a2258 |
12 | 43098a716861 |
13 | 19c232965831 |
14 | ad07c9ba929 |
15 | 573b45eb09a |
hex | 2e03451b249 |
3161973699145 has 4 divisors (see below), whose sum is σ = 3794368438980. Its totient is φ = 2529578959312.
The previous prime is 3161973699133. The next prime is 3161973699151. The reversal of 3161973699145 is 5419963791613.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2050933323664 + 1111040375481 = 1432108^2 + 1054059^2 .
It is a cyclic number.
It is not a de Polignac number, because 3161973699145 - 211 = 3161973697097 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316197369910 + ... + 316197369919.
It is an arithmetic number, because the mean of its divisors is an integer number (948592109745).
Almost surely, 23161973699145 is an apocalyptic number.
It is an amenable number.
3161973699145 is a deficient number, since it is larger than the sum of its proper divisors (632394739835).
3161973699145 is an equidigital number, since it uses as much as digits as its factorization.
3161973699145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 632394739834.
The product of its digits is 33067440, while the sum is 64.
The spelling of 3161973699145 in words is "three trillion, one hundred sixty-one billion, nine hundred seventy-three million, six hundred ninety-nine thousand, one hundred forty-five".
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