Base | Representation |
---|---|
bin | 101110000001000010110… |
… | …101011111110101000001 |
3 | 102012022020100122101210121 |
4 | 232001002311133311001 |
5 | 403302210104000423 |
6 | 10420411430100241 |
7 | 444314456063245 |
oct | 56010265376501 |
9 | 12168210571717 |
10 | 3162217250113 |
11 | 100a0a8220749 |
12 | 430a381aa681 |
13 | 19c27125aa2c |
14 | ad0a3098425 |
15 | 573caba945d |
hex | 2e042d5fd41 |
3162217250113 has 4 divisors (see below), whose sum is σ = 3162236521408. Its totient is φ = 3162197978820.
The previous prime is 3162217250057. The next prime is 3162217250119. The reversal of 3162217250113 is 3110527122613.
3162217250113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3162217250113 - 213 = 3162217241921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3162217250119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9387381 + ... + 9718402.
It is an arithmetic number, because the mean of its divisors is an integer number (790559130352).
Almost surely, 23162217250113 is an apocalyptic number.
It is an amenable number.
3162217250113 is a deficient number, since it is larger than the sum of its proper divisors (19271295).
3162217250113 is a wasteful number, since it uses less digits than its factorization.
3162217250113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19271294.
The product of its (nonzero) digits is 15120, while the sum is 34.
The spelling of 3162217250113 in words is "three trillion, one hundred sixty-two billion, two hundred seventeen million, two hundred fifty thousand, one hundred thirteen".
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