Base | Representation |
---|---|
bin | 100011111101100010000010… |
… | …0111111001001100111111111 |
3 | 1112110222220112201212201210020 |
4 | 1013323010010333021213333 |
5 | 312430042111242441323 |
6 | 3040431243414143223 |
7 | 123425242463141304 |
oct | 10773040477114777 |
9 | 1473886481781706 |
10 | 316320130046463 |
11 | 91875682a65024 |
12 | 2b588b63651b13 |
13 | 10766b2502a30a |
14 | 5817d941510ab |
15 | 268832c2a1ae3 |
hex | 11fb104fc99ff |
316320130046463 has 16 divisors (see below), whose sum is σ = 426506135084640. Its totient is φ = 208507184557056.
The previous prime is 316320130046443. The next prime is 316320130046509. The reversal of 316320130046463 is 364640031023613.
It is not a de Polignac number, because 316320130046463 - 221 = 316320127949311 is a prime.
It is a super-2 number, since 2×3163201300464632 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (316320130046443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6318231 + ... + 25933767.
It is an arithmetic number, because the mean of its divisors is an integer number (26656633442790).
Almost surely, 2316320130046463 is an apocalyptic number.
316320130046463 is a deficient number, since it is larger than the sum of its proper divisors (110186005038177).
316320130046463 is a wasteful number, since it uses less digits than its factorization.
316320130046463 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19676026.
The product of its (nonzero) digits is 559872, while the sum is 42.
The spelling of 316320130046463 in words is "three hundred sixteen trillion, three hundred twenty billion, one hundred thirty million, forty-six thousand, four hundred sixty-three".
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