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316380351300 = 2235213172280703
BaseRepresentation
bin1001001101010011011…
…11010000101101000100
31010020122002110002102220
410212221233100231010
520140421332220200
6401202040532340
731600125420516
oct4465157205504
91106562402386
10316380351300
111121a3507712
12513971810b0
1323ab0636b80
1411454801bb6
15836a7864a0
hex49a9bd0b44

316380351300 has 216 divisors, whose sum is σ = 1047212307456. Its totient is φ = 73296906240.

The previous prime is 316380351299. The next prime is 316380351311. The reversal of 316380351300 is 3153083613.

It is a super-2 number, since 2×3163803513002 (a number of 24 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 986749 + ... + 1267451.

Almost surely, 2316380351300 is an apocalyptic number.

316380351300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 316380351300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (523606153728).

316380351300 is an abundant number, since it is smaller than the sum of its proper divisors (730831956156).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

316380351300 is a wasteful number, since it uses less digits than its factorization.

316380351300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 280767 (or 280743 counting only the distinct ones).

The product of its (nonzero) digits is 19440, while the sum is 33.

The spelling of 316380351300 in words is "three hundred sixteen billion, three hundred eighty million, three hundred fifty-one thousand, three hundred".