316402462133 has 4 divisors (see below), whose sum is σ = 316403654700. Its totient is φ = 316401269568.

The previous prime is 316402462111. The next prime is 316402462139. The reversal of 316402462133 is 331264204613.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 297987157924 + 18415304209 = 545882^2 + 135703^2 .

It is a cyclic number.

It is not a de Polignac number, because 316402462133 - 2¹² = 316402458037 is a prime.

It is a super-2 number, since 2×316402462133² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 316402462093 and 316402462102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (316402462139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1343 + ... + 795491.

It is an arithmetic number, because the mean of its divisors is an integer number (79100913675).

Almost surely, 2^316402462133 is an apocalyptic number.

It is an amenable number.

316402462133 is a deficient number, since it is larger than the sum of its proper divisors (1192567).

316402462133 is an equidigital number, since it uses as much as digits as its factorization.

316402462133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1192566.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 316402462133 its reverse (331264204613), we get a palindrome (647666666746).

The spelling of 316402462133 in words is "three hundred sixteen billion, four hundred two million, four hundred sixty-two thousand, one hundred thirty-three".