Base | Representation |
---|---|
bin | 100011111110001000110001… |
… | …1001110101011011100110010 |
3 | 1112111021212021002002100202110 |
4 | 1013330101203032223130302 |
5 | 312432422442240212343 |
6 | 3040533402044230150 |
7 | 123434246055243213 |
oct | 10774214316533462 |
9 | 1474255232070673 |
10 | 316403315554098 |
11 | 918a7990016143 |
12 | 2b5a10ba23b356 |
13 | 107719210c8396 |
14 | 581c005dc140a |
15 | 268a59a259833 |
hex | 11fc4633ab732 |
316403315554098 has 16 divisors (see below), whose sum is σ = 640430807387616. Its totient is φ = 104197075804800.
The previous prime is 316403315554031. The next prime is 316403315554127. The reversal of 316403315554098 is 890455513304613.
It is a super-2 number, since 2×3164033155540982 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 317674011103 + ... + 317674012098.
It is an arithmetic number, because the mean of its divisors is an integer number (40026925461726).
Almost surely, 2316403315554098 is an apocalyptic number.
316403315554098 is an abundant number, since it is smaller than the sum of its proper divisors (324027491833518).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
316403315554098 is a wasteful number, since it uses less digits than its factorization.
316403315554098 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 635348023289.
The product of its (nonzero) digits is 23328000, while the sum is 57.
The spelling of 316403315554098 in words is "three hundred sixteen trillion, four hundred three billion, three hundred fifteen million, five hundred fifty-four thousand, ninety-eight".
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