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316491139147 = 931793396593
BaseRepresentation
bin1001001101100000101…
…01111000100001001011
31010020220210220200210111
410212300111320201023
520141133212423042
6401221035255151
731602642203251
oct4466025704113
91106823820714
10316491139147
1111224aaa7217
12514082aa4b7
1323aca586a01
14114654005d1
15837536c517
hex49b057884b

316491139147 has 4 divisors (see below), whose sum is σ = 316494628920. Its totient is φ = 316487649376.

The previous prime is 316491139121. The next prime is 316491139171. The reversal of 316491139147 is 741931194613.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 316491139147 - 219 = 316490614859 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 316491139147.

It is not an unprimeable number, because it can be changed into a prime (316491139117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1605118 + ... + 1791475.

It is an arithmetic number, because the mean of its divisors is an integer number (79123657230).

Almost surely, 2316491139147 is an apocalyptic number.

316491139147 is a deficient number, since it is larger than the sum of its proper divisors (3489773).

316491139147 is an equidigital number, since it uses as much as digits as its factorization.

316491139147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3489772.

The product of its digits is 489888, while the sum is 49.

The spelling of 316491139147 in words is "three hundred sixteen billion, four hundred ninety-one million, one hundred thirty-nine thousand, one hundred forty-seven".

Divisors: 1 93179 3396593 316491139147