Base | Representation |
---|---|
bin | 1011110011011001… |
… | …0100001011100001 |
3 | 22011210211010001000 |
4 | 2330312110023201 |
5 | 22442044330131 |
6 | 1242220502213 |
7 | 141341400465 |
oct | 27466241341 |
9 | 8153733030 |
10 | 3168355041 |
11 | 13864aa045 |
12 | 7450aa969 |
13 | 3b653bbc7 |
14 | 220b0c4a5 |
15 | 13824bce6 |
hex | bcd942e1 |
3168355041 has 24 divisors (see below), whose sum is σ = 4906835360. Its totient is φ = 2020391208.
The previous prime is 3168355033. The next prime is 3168355061. The reversal of 3168355041 is 1405538613.
3168355041 is a `hidden beast` number, since 3 + 1 + 68 + 3 + 550 + 41 = 666.
3168355041 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3168355041 - 23 = 3168355033 is a prime.
It is a super-2 number, since 2×31683550412 = 20076947331660223362, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3168354987 and 3168355005.
It is not an unprimeable number, because it can be changed into a prime (3168355061) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 96631 + ... + 125196.
Almost surely, 23168355041 is an apocalyptic number.
It is an amenable number.
3168355041 is a deficient number, since it is larger than the sum of its proper divisors (1738480319).
3168355041 is a wasteful number, since it uses less digits than its factorization.
3168355041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 221882 (or 221853 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 36.
The square root of 3168355041 is about 56288.1429876666. The cubic root of 3168355041 is about 1468.7389560033.
The spelling of 3168355041 in words is "three billion, one hundred sixty-eight million, three hundred fifty-five thousand, forty-one".
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