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317540113 = 1128867283
BaseRepresentation
bin10010111011010…
…100011100010001
3211010111201010221
4102323110130101
51122242240423
651301553041
710604021632
oct2273243421
9733451127
10317540113
11153274650
128a415781
1350a2c677
143025b889
151cd25e5d
hex12ed4711

317540113 has 4 divisors (see below), whose sum is σ = 346407408. Its totient is φ = 288672820.

The previous prime is 317540101. The next prime is 317540129. The reversal of 317540113 is 311045713.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 317540113 - 25 = 317540081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (317540213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14433631 + ... + 14433652.

It is an arithmetic number, because the mean of its divisors is an integer number (86601852).

Almost surely, 2317540113 is an apocalyptic number.

It is an amenable number.

317540113 is a deficient number, since it is larger than the sum of its proper divisors (28867295).

317540113 is a wasteful number, since it uses less digits than its factorization.

317540113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28867294.

The product of its (nonzero) digits is 1260, while the sum is 25.

The square root of 317540113 is about 17819.6552435786. The cubic root of 317540113 is about 682.2332236126.

Adding to 317540113 its reverse (311045713), we get a palindrome (628585826).

The spelling of 317540113 in words is "three hundred seventeen million, five hundred forty thousand, one hundred thirteen".

Divisors: 1 11 28867283 317540113