Base | Representation |
---|---|
bin | 101110100100010110110… |
… | …000110100111100010011 |
3 | 102022221002201221101110111 |
4 | 232210112300310330103 |
5 | 404412332412042120 |
6 | 10450042014142151 |
7 | 450126160504513 |
oct | 56442660647423 |
9 | 12287081841414 |
10 | 3200132534035 |
11 | 102419442a738 |
12 | 438259ab1957 |
13 | 1a2a04444088 |
14 | b0c5c837843 |
15 | 5839964775a |
hex | 2e916c34f13 |
3200132534035 has 32 divisors (see below), whose sum is σ = 3898373806080. Its totient is φ = 2521580160000.
The previous prime is 3200132534023. The next prime is 3200132534069. The reversal of 3200132534035 is 5304352310023.
3200132534035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a de Polignac number, because none of the positive numbers 2k-3200132534035 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3200132533988 and 3200132534006.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 135420601 + ... + 135444229.
It is an arithmetic number, because the mean of its divisors is an integer number (121824181440).
Almost surely, 23200132534035 is an apocalyptic number.
3200132534035 is a deficient number, since it is larger than the sum of its proper divisors (698241272045).
3200132534035 is a wasteful number, since it uses less digits than its factorization.
3200132534035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25119.
The product of its (nonzero) digits is 32400, while the sum is 31.
Adding to 3200132534035 its reverse (5304352310023), we get a palindrome (8504484844058).
The spelling of 3200132534035 in words is "three trillion, two hundred billion, one hundred thirty-two million, five hundred thirty-four thousand, thirty-five".
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