Base | Representation |
---|---|
bin | 101110100100100001100… |
… | …011010101001001110101 |
3 | 102022221120100112201021122 |
4 | 232210201203111021311 |
5 | 404413220231422313 |
6 | 10450112001553325 |
7 | 450133516204322 |
oct | 56444143251165 |
9 | 12287510481248 |
10 | 3200313545333 |
11 | 1024277623153 |
12 | 4382aa645845 |
13 | 1a2a32ab0358 |
14 | b0c788b5b49 |
15 | 583aa4a0708 |
hex | 2e9218d5275 |
3200313545333 has 8 divisors (see below), whose sum is σ = 3204048806400. Its totient is φ = 3196578536928.
The previous prime is 3200313545293. The next prime is 3200313545339. The reversal of 3200313545333 is 3335453130023.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3200313545333 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3200313545293 and 3200313545302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3200313545339) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39799913 + ... + 39880241.
It is an arithmetic number, because the mean of its divisors is an integer number (400506100800).
Almost surely, 23200313545333 is an apocalyptic number.
It is an amenable number.
3200313545333 is a deficient number, since it is larger than the sum of its proper divisors (3735261067).
3200313545333 is an equidigital number, since it uses as much as digits as its factorization.
3200313545333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 126331.
The product of its (nonzero) digits is 145800, while the sum is 35.
Adding to 3200313545333 its reverse (3335453130023), we get a palindrome (6535766675356).
The spelling of 3200313545333 in words is "three trillion, two hundred billion, three hundred thirteen million, five hundred forty-five thousand, three hundred thirty-three".
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