Base | Representation |
---|---|
bin | 1001010100001001100… |
… | …01011100110011101111 |
3 | 1010121010012012110122100 |
4 | 10222010301130303233 |
5 | 20220433103313341 |
6 | 403010432150143 |
7 | 32060156523141 |
oct | 4520461346357 |
9 | 1117105173570 |
10 | 320055135471 |
11 | 113809864425 |
12 | 52041998353 |
13 | 24247a6c286 |
14 | 116c289ac91 |
15 | 84d31bb3b6 |
hex | 4a84c5ccef |
320055135471 has 12 divisors (see below), whose sum is σ = 462324943080. Its totient is φ = 213359437680.
The previous prime is 320055135461. The next prime is 320055135551. The reversal of 320055135471 is 174531550023.
320055135471 is a `hidden beast` number, since 3 + 2 + 0 + 0 + 55 + 135 + 471 = 666.
It is not a de Polignac number, because 320055135471 - 27 = 320055135343 is a prime.
It is a super-3 number, since 3×3200551354713 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (320055135461) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 695241 + ... + 1059938.
It is an arithmetic number, because the mean of its divisors is an integer number (38527078590).
Almost surely, 2320055135471 is an apocalyptic number.
320055135471 is a deficient number, since it is larger than the sum of its proper divisors (142269807609).
320055135471 is a wasteful number, since it uses less digits than its factorization.
320055135471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1775446 (or 1775443 counting only the distinct ones).
The product of its (nonzero) digits is 63000, while the sum is 36.
Adding to 320055135471 its reverse (174531550023), we get a palindrome (494586685494).
The spelling of 320055135471 in words is "three hundred twenty billion, fifty-five million, one hundred thirty-five thousand, four hundred seventy-one".
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