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3201023033114 = 21600511516557
BaseRepresentation
bin101110100101001011110…
…101110011111100011010
3102100000101210120102112212
4232211023311303330122
5404421143344024424
610450310224435122
7450160222562654
oct56451365637432
912300353512485
103201023033114
111024601062895
12438468178aa2
131a2b16a920ca
14b0d04bdd6d4
15583ec8e910e
hex2e94bd73f1a

3201023033114 has 4 divisors (see below), whose sum is σ = 4801534549674. Its totient is φ = 1600511516556.

The previous prime is 3201023033113. The next prime is 3201023033123. The reversal of 3201023033114 is 4113303201023.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 2797982162089 + 403040871025 = 1672717^2 + 634855^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 3201023033114.

It is not an unprimeable number, because it can be changed into a prime (3201023033113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 800255758277 + ... + 800255758280.

Almost surely, 23201023033114 is an apocalyptic number.

3201023033114 is a deficient number, since it is larger than the sum of its proper divisors (1600511516560).

3201023033114 is a wasteful number, since it uses less digits than its factorization.

3201023033114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1600511516559.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 3201023033114 its reverse (4113303201023), we get a palindrome (7314326234137).

The spelling of 3201023033114 in words is "three trillion, two hundred one billion, twenty-three million, thirty-three thousand, one hundred fourteen".

Divisors: 1 2 1600511516557 3201023033114