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32013041065 = 56402608213
BaseRepresentation
bin11101110100001000…
…000011110110101001
310001122001011222120121
4131310020003312221
51011030314303230
622412342323241
72212212234145
oct356410036651
9101561158517
1032013041065
1112638588635
126255129521
133032457265
14179993a225
15c7571577a
hex774203da9

32013041065 has 4 divisors (see below), whose sum is σ = 38415649284. Its totient is φ = 25610432848.

The previous prime is 32013041017. The next prime is 32013041077. The reversal of 32013041065 is 56014031023.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6185979801 + 25827061264 = 78651^2 + 160708^2 .

It is a cyclic number.

It is not a de Polignac number, because 32013041065 - 27 = 32013040937 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3201304102 + ... + 3201304111.

It is an arithmetic number, because the mean of its divisors is an integer number (9603912321).

Almost surely, 232013041065 is an apocalyptic number.

It is an amenable number.

32013041065 is a deficient number, since it is larger than the sum of its proper divisors (6402608219).

32013041065 is an equidigital number, since it uses as much as digits as its factorization.

32013041065 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6402608218.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 32013041065 its reverse (56014031023), we get a palindrome (88027072088).

The spelling of 32013041065 in words is "thirty-two billion, thirteen million, forty-one thousand, sixty-five".

Divisors: 1 5 6402608213 32013041065