Base | Representation |
---|---|
bin | 11101110100001000… |
… | …000011110110101001 |
3 | 10001122001011222120121 |
4 | 131310020003312221 |
5 | 1011030314303230 |
6 | 22412342323241 |
7 | 2212212234145 |
oct | 356410036651 |
9 | 101561158517 |
10 | 32013041065 |
11 | 12638588635 |
12 | 6255129521 |
13 | 3032457265 |
14 | 179993a225 |
15 | c7571577a |
hex | 774203da9 |
32013041065 has 4 divisors (see below), whose sum is σ = 38415649284. Its totient is φ = 25610432848.
The previous prime is 32013041017. The next prime is 32013041077. The reversal of 32013041065 is 56014031023.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6185979801 + 25827061264 = 78651^2 + 160708^2 .
It is a cyclic number.
It is not a de Polignac number, because 32013041065 - 27 = 32013040937 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3201304102 + ... + 3201304111.
It is an arithmetic number, because the mean of its divisors is an integer number (9603912321).
Almost surely, 232013041065 is an apocalyptic number.
It is an amenable number.
32013041065 is a deficient number, since it is larger than the sum of its proper divisors (6402608219).
32013041065 is an equidigital number, since it uses as much as digits as its factorization.
32013041065 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6402608218.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 32013041065 its reverse (56014031023), we get a palindrome (88027072088).
The spelling of 32013041065 in words is "thirty-two billion, thirteen million, forty-one thousand, sixty-five".
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