Base | Representation |
---|---|
bin | 11101110100001001… |
… | …000011111010010101 |
3 | 10001122001200022111101 |
4 | 131310021003322111 |
5 | 1011030401202240 |
6 | 22412352110101 |
7 | 2212214406124 |
oct | 356411037225 |
9 | 101561608441 |
10 | 32013303445 |
11 | 12638747782 |
12 | 6255235331 |
13 | 3032519806 |
14 | 17999a7abb |
15 | c7576839a |
hex | 774243e95 |
32013303445 has 4 divisors (see below), whose sum is σ = 38415964140. Its totient is φ = 25610642752.
The previous prime is 32013303409. The next prime is 32013303559. The reversal of 32013303445 is 54430331023.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54430331023 = 147409 ⋅369247.
It can be written as a sum of positive squares in 2 ways, for example, as 25230463281 + 6782840164 = 158841^2 + 82358^2 .
It is a cyclic number.
It is not a de Polignac number, because 32013303445 - 27 = 32013303317 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3201330340 + ... + 3201330349.
It is an arithmetic number, because the mean of its divisors is an integer number (9603991035).
Almost surely, 232013303445 is an apocalyptic number.
It is an amenable number.
32013303445 is a deficient number, since it is larger than the sum of its proper divisors (6402660695).
32013303445 is an equidigital number, since it uses as much as digits as its factorization.
32013303445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6402660694.
The product of its (nonzero) digits is 12960, while the sum is 28.
Adding to 32013303445 its reverse (54430331023), we get a palindrome (86443634468).
The spelling of 32013303445 in words is "thirty-two billion, thirteen million, three hundred three thousand, four hundred forty-five".
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