Base | Representation |
---|---|
bin | 100100011001010010000000… |
… | …1101101011110011101111001 |
3 | 1112222111111211022102021111212 |
4 | 1020302210001231132131321 |
5 | 313430033421021243231 |
6 | 3052511310532532505 |
7 | 124300630051201355 |
oct | 11062440155363571 |
9 | 1488444738367455 |
10 | 320134006040441 |
11 | 9300608459610a |
12 | 2baa4146a81135 |
13 | 109826795182b8 |
14 | 590a7d6206465 |
15 | 27026480c342b |
hex | 1232901b5e779 |
320134006040441 has 4 divisors (see below), whose sum is σ = 320137570342800. Its totient is φ = 320130441738084.
The previous prime is 320134006040393. The next prime is 320134006040467. The reversal of 320134006040441 is 144040600431023.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 320134006040441 - 214 = 320134006024057 is a prime.
It is a super-2 number, since 2×3201340060404412 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 320134006040398 and 320134006040407.
It is not an unprimeable number, because it can be changed into a prime (320134006040041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1782016451 + ... + 1782196088.
It is an arithmetic number, because the mean of its divisors is an integer number (80034392585700).
Almost surely, 2320134006040441 is an apocalyptic number.
It is an amenable number.
320134006040441 is a deficient number, since it is larger than the sum of its proper divisors (3564302359).
320134006040441 is an equidigital number, since it uses as much as digits as its factorization.
320134006040441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3564302358.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 320134006040441 its reverse (144040600431023), we get a palindrome (464174606471464).
The spelling of 320134006040441 in words is "three hundred twenty trillion, one hundred thirty-four billion, six million, forty thousand, four hundred forty-one".
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