Base | Representation |
---|---|
bin | 1001010100010101000… |
… | …00011111000000101101 |
3 | 1010121100220020202000002 |
4 | 10222022200133000231 |
5 | 20221132221220331 |
6 | 403024150314045 |
7 | 32062435404653 |
oct | 4521240370055 |
9 | 1117326222002 |
10 | 320151351341 |
11 | 113859100878 |
12 | 5206a058925 |
13 | 24261989543 |
14 | 116d1584dd3 |
15 | 84db8749cb |
hex | 4a8a81f02d |
320151351341 has 4 divisors (see below), whose sum is σ = 323259616992. Its totient is φ = 317043085692.
The previous prime is 320151351319. The next prime is 320151351343. The reversal of 320151351341 is 143153151023.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 320151351341 - 218 = 320151089197 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (320151351343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1554132671 + ... + 1554132876.
It is an arithmetic number, because the mean of its divisors is an integer number (80814904248).
Almost surely, 2320151351341 is an apocalyptic number.
It is an amenable number.
320151351341 is a deficient number, since it is larger than the sum of its proper divisors (3108265651).
320151351341 is a wasteful number, since it uses less digits than its factorization.
320151351341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3108265650.
The product of its (nonzero) digits is 5400, while the sum is 29.
The spelling of 320151351341 in words is "three hundred twenty billion, one hundred fifty-one million, three hundred fifty-one thousand, three hundred forty-one".
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