Base | Representation |
---|---|
bin | 101110100111001111111… |
… | …111011000010111100011 |
3 | 102100020010022102211100202 |
4 | 232213033333120113203 |
5 | 404440213433242430 |
6 | 10451314224535415 |
7 | 450266163615200 |
oct | 56471777302743 |
9 | 12306108384322 |
10 | 3203240134115 |
11 | 102553960266a |
12 | 43898678156b |
13 | 1a30ab2004a8 |
14 | b107544cca7 |
15 | 584cc392d45 |
hex | 2e9cffd85e3 |
3203240134115 has 24 divisors (see below), whose sum is σ = 4474501984512. Its totient is φ = 2195014066560.
The previous prime is 3203240134103. The next prime is 3203240134151. The reversal of 3203240134115 is 5114310423023.
It is not a de Polignac number, because 3203240134115 - 24 = 3203240134099 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4083674 + ... + 4804463.
It is an arithmetic number, because the mean of its divisors is an integer number (186437582688).
Almost surely, 23203240134115 is an apocalyptic number.
3203240134115 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
3203240134115 is a deficient number, since it is larger than the sum of its proper divisors (1271261850397).
3203240134115 is a wasteful number, since it uses less digits than its factorization.
3203240134115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8889627 (or 8889620 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 3203240134115 its reverse (5114310423023), we get a palindrome (8317550557138).
The spelling of 3203240134115 in words is "three trillion, two hundred three billion, two hundred forty million, one hundred thirty-four thousand, one hundred fifteen".
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