3204211312031 has 4 divisors (see below), whose sum is σ = 3209289302064. Its totient is φ = 3199133322000.

The previous prime is 3204211312021. The next prime is 3204211312033. The reversal of 3204211312031 is 1302131124023.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3204211312031 is a prime.

It is a super-4 number, since 4×3204211312031⁴ (a number of 51 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3204211311988 and 3204211312006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3204211312033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2538994070 + ... + 2538995331.

It is an arithmetic number, because the mean of its divisors is an integer number (802322325516).

Almost surely, 2^{3204211312031} is an apocalyptic number.

3204211312031 is a deficient number, since it is larger than the sum of its proper divisors (5077990033).

3204211312031 is an equidigital number, since it uses as much as digits as its factorization.

3204211312031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5077990032.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 3204211312031 its reverse (1302131124023), we get a palindrome (4506342436054).

The spelling of 3204211312031 in words is "three trillion, two hundred four billion, two hundred eleven million, three hundred twelve thousand, thirty-one".