3204434131 has 4 divisors (see below), whose sum is σ = 3204559512. Its totient is φ = 3204308752.

The previous prime is 3204434117. The next prime is 3204434161. The reversal of 3204434131 is 1314344023.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1314344023 = 107 ⋅12283589.

It is a cyclic number.

It is not a de Polignac number, because 3204434131 - 2³¹ = 1056950483 is a prime.

It is a super-2 number, since 2×3204434131² = 20536796199835450322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3204434096 and 3204434105.

It is not an unprimeable number, because it can be changed into a prime (3204434161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9061 + ... + 80566.

It is an arithmetic number, because the mean of its divisors is an integer number (801139878).

Almost surely, 2^3204434131 is an apocalyptic number.

3204434131 is a deficient number, since it is larger than the sum of its proper divisors (125381).

3204434131 is an equidigital number, since it uses as much as digits as its factorization.

3204434131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125380.

The product of its (nonzero) digits is 3456, while the sum is 25.

The square root of 3204434131 is about 56607.7214786110. The cubic root of 3204434131 is about 1474.2929302438.

Adding to 3204434131 its reverse (1314344023), we get a palindrome (4518778154).

The spelling of 3204434131 in words is "three billion, two hundred four million, four hundred thirty-four thousand, one hundred thirty-one".