Base | Representation |
---|---|
bin | 11101111001100011… |
… | …000101101000111001 |
3 | 10001212101100210201021 |
4 | 131321203011220321 |
5 | 1011222111343340 |
6 | 22425352222441 |
7 | 2214365413426 |
oct | 357143055071 |
9 | 101771323637 |
10 | 32104012345 |
11 | 12684972709 |
12 | 627b69aa21 |
13 | 3048259312 |
14 | 17a7a5ad4d |
15 | c7d6d4e4a |
hex | 7798c5a39 |
32104012345 has 4 divisors (see below), whose sum is σ = 38524814820. Its totient is φ = 25683209872.
The previous prime is 32104012327. The next prime is 32104012349. The reversal of 32104012345 is 54321040123.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 17227087504 + 14876924841 = 131252^2 + 121971^2 .
It is a cyclic number.
It is not a de Polignac number, because 32104012345 - 25 = 32104012313 is a prime.
It is not an unprimeable number, because it can be changed into a prime (32104012349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3210401230 + ... + 3210401239.
It is an arithmetic number, because the mean of its divisors is an integer number (9631203705).
Almost surely, 232104012345 is an apocalyptic number.
It is an amenable number.
32104012345 is a deficient number, since it is larger than the sum of its proper divisors (6420802475).
32104012345 is an equidigital number, since it uses as much as digits as its factorization.
32104012345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6420802474.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 32104012345 its reverse (54321040123), we get a palindrome (86425052468).
The spelling of 32104012345 in words is "thirty-two billion, one hundred four million, twelve thousand, three hundred forty-five".
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