32104251420133 has 4 divisors (see below), whose sum is σ = 32104266620608. Its totient is φ = 32104236219660.

The previous prime is 32104251420103. The next prime is 32104251420139. The reversal of 32104251420133 is 33102415240123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-32104251420133 is a prime.

It is a super-2 number, since 2×32104251420133² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 32104251420095 and 32104251420104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32104251420139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3798141 + ... + 8867602.

It is an arithmetic number, because the mean of its divisors is an integer number (8026066655152).

Almost surely, 2^{32104251420133} is an apocalyptic number.

It is an amenable number.

32104251420133 is a deficient number, since it is larger than the sum of its proper divisors (15200475).

32104251420133 is a wasteful number, since it uses less digits than its factorization.

32104251420133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15200474.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 32104251420133 its reverse (33102415240123), we get a palindrome (65206666660256).

The spelling of 32104251420133 in words is "thirty-two trillion, one hundred four billion, two hundred fifty-one million, four hundred twenty thousand, one hundred thirty-three".