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321113000122 = 21571102200191
BaseRepresentation
bin1001010110000111101…
…00111000100010111010
31010200211220202120010121
410223003310320202322
520230114412000442
6403303422003454
732125323315505
oct4530364704272
91120756676117
10321113000122
11114201a0a832
125229811658a
1324385c894a5
141178318c13c
158545ecc967
hex4ac3d388ba

321113000122 has 8 divisors (see below), whose sum is σ = 481976105472. Its totient is φ = 160454298300.

The previous prime is 321113000107. The next prime is 321113000177. The reversal of 321113000122 is 221000311123.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×3211130001223 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 321113000096 and 321113000105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51096954 + ... + 51103237.

It is an arithmetic number, because the mean of its divisors is an integer number (60247013184).

Almost surely, 2321113000122 is an apocalyptic number.

321113000122 is a deficient number, since it is larger than the sum of its proper divisors (160863105350).

321113000122 is a wasteful number, since it uses less digits than its factorization.

321113000122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102201764.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 321113000122 its reverse (221000311123), we get a palindrome (542113311245).

The spelling of 321113000122 in words is "three hundred twenty-one billion, one hundred thirteen million, one hundred twenty-two", and thus it is an aban number.

Divisors: 1 2 1571 3142 102200191 204400382 160556500061 321113000122