Base | Representation |
---|---|
bin | 1110100110100101010001… |
… | …00011010001000011110111 |
3 | 11012200212200201112220010012 |
4 | 13103102220203101003313 |
5 | 13202110340322301403 |
6 | 152144014540050435 |
7 | 6523005243414035 |
oct | 723225043210367 |
9 | 135625621486105 |
10 | 32112003322103 |
11 | a260695798551 |
12 | 3727630b33a1b |
13 | 14bc1c223b9c3 |
14 | 7d032d101555 |
15 | 3aa490bbaed8 |
hex | 1d34a88d10f7 |
32112003322103 has 4 divisors (see below), whose sum is σ = 32112060776640. Its totient is φ = 32111945867568.
The previous prime is 32112003322081. The next prime is 32112003322129. The reversal of 32112003322103 is 30122330021123.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 32112003322103 - 238 = 31837125415159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32112003022103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27880583 + ... + 29009496.
It is an arithmetic number, because the mean of its divisors is an integer number (8028015194160).
Almost surely, 232112003322103 is an apocalyptic number.
32112003322103 is a deficient number, since it is larger than the sum of its proper divisors (57454537).
32112003322103 is an equidigital number, since it uses as much as digits as its factorization.
32112003322103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57454536.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 32112003322103 its reverse (30122330021123), we get a palindrome (62234333343226).
The spelling of 32112003322103 in words is "thirty-two trillion, one hundred twelve billion, three million, three hundred twenty-two thousand, one hundred three".
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