Base | Representation |
---|---|
bin | 1110100110100101100000… |
… | …10110101100010001001011 |
3 | 11012200220000211220101101020 |
4 | 13103102300112230101023 |
5 | 13202111122331242103 |
6 | 152144035534123523 |
7 | 6523011423262554 |
oct | 723226026542113 |
9 | 135626024811336 |
10 | 32112134243403 |
11 | a260752689675 |
12 | 37276689505a3 |
13 | 14bc2133ba926 |
14 | 7d034266132b |
15 | 3aa49c42c753 |
hex | 1d34b05ac44b |
32112134243403 has 8 divisors (see below), whose sum is σ = 43419223766016. Its totient is φ = 21106567108200.
The previous prime is 32112134243393. The next prime is 32112134243473. The reversal of 32112134243403 is 30434243121123.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 32112134243403 - 210 = 32112134242379 is a prime.
It is not an unprimeable number, because it can be changed into a prime (32112134243473) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75380596603 + ... + 75380597028.
It is an arithmetic number, because the mean of its divisors is an integer number (5427402970752).
Almost surely, 232112134243403 is an apocalyptic number.
32112134243403 is a deficient number, since it is larger than the sum of its proper divisors (11307089522613).
32112134243403 is a wasteful number, since it uses less digits than its factorization.
32112134243403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 150761193705.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 32112134243403 its reverse (30434243121123), we get a palindrome (62546377364526).
The spelling of 32112134243403 in words is "thirty-two trillion, one hundred twelve billion, one hundred thirty-four million, two hundred forty-three thousand, four hundred three".
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