Base | Representation |
---|---|
bin | 1110100110100101100000… |
… | …10110101100010010010001 |
3 | 11012200220000211220101110211 |
4 | 13103102300112230102101 |
5 | 13202111122331242343 |
6 | 152144035534124121 |
7 | 6523011423263014 |
oct | 723226026542221 |
9 | 135626024811424 |
10 | 32112134243473 |
11 | a260752689729 |
12 | 3727668950641 |
13 | 14bc2133ba97b |
14 | 7d034266137b |
15 | 3aa49c42c79d |
hex | 1d34b05ac491 |
32112134243473 has 2 divisors, whose sum is σ = 32112134243474. Its totient is φ = 32112134243472.
The previous prime is 32112134243393. The next prime is 32112134243489. The reversal of 32112134243473 is 37434243121123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 24551460133249 + 7560674110224 = 4954943^2 + 2749668^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32112134243473 is a prime.
It is not a weakly prime, because it can be changed into another prime (32112134243773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16056067121736 + 16056067121737.
It is an arithmetic number, because the mean of its divisors is an integer number (16056067121737).
Almost surely, 232112134243473 is an apocalyptic number.
It is an amenable number.
32112134243473 is a deficient number, since it is larger than the sum of its proper divisors (1).
32112134243473 is an equidigital number, since it uses as much as digits as its factorization.
32112134243473 is an evil number, because the sum of its binary digits is even.
The product of its digits is 290304, while the sum is 40.
Adding to 32112134243473 its reverse (37434243121123), we get a palindrome (69546377364596).
The spelling of 32112134243473 in words is "thirty-two trillion, one hundred twelve billion, one hundred thirty-four million, two hundred forty-three thousand, four hundred seventy-three".
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