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32113120220023 = 178717970408629
BaseRepresentation
bin1110100110100111010110…
…00111111001001101110111
311012200222120120012012000211
413103103223013321031313
513202120132234020043
6152144321435050251
76523045025036143
oct723235307711567
9135628516165024
1032113120220023
11a2611091a4487
1237278a2ba0987
1314bc33c757b4b
147d03d759c223
153aa508c8da9d
hex1d34eb1f9377

32113120220023 has 4 divisors (see below), whose sum is σ = 32131090630440. Its totient is φ = 32095149809608.

The previous prime is 32113120219991. The next prime is 32113120220087. The reversal of 32113120220023 is 32002202131123.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 32113120220023 - 25 = 32113120219991 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 32113120219976 and 32113120220003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32113120221023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8985202528 + ... + 8985206101.

It is an arithmetic number, because the mean of its divisors is an integer number (8032772657610).

Almost surely, 232113120220023 is an apocalyptic number.

32113120220023 is a deficient number, since it is larger than the sum of its proper divisors (17970410417).

32113120220023 is a wasteful number, since it uses less digits than its factorization.

32113120220023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17970410416.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 32113120220023 its reverse (32002202131123), we get a palindrome (64115322351146).

The spelling of 32113120220023 in words is "thirty-two trillion, one hundred thirteen billion, one hundred twenty million, two hundred twenty thousand, twenty-three".

Divisors: 1 1787 17970408629 32113120220023