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32113201303 = 61842362501
BaseRepresentation
bin11101111010000110…
…001001000010010111
310001220000122122121001
4131322012021002113
51011231434420203
622430321204131
72214536464411
oct357206110227
9101800578531
1032113201303
111268a079497
126282790647
13304a125981
1417a8d6d9b1
15c7e3ec91d
hex77a189097

32113201303 has 8 divisors (see below), whose sum is σ = 32644044576. Its totient is φ = 31582500000.

The previous prime is 32113201279. The next prime is 32113201313. The reversal of 32113201303 is 30310231123.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 32113201303 - 213 = 32113193111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32113201313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 482553 + ... + 545053.

It is an arithmetic number, because the mean of its divisors is an integer number (4080505572).

Almost surely, 232113201303 is an apocalyptic number.

32113201303 is a deficient number, since it is larger than the sum of its proper divisors (530843273).

32113201303 is an equidigital number, since it uses as much as digits as its factorization.

32113201303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70985.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 32113201303 its reverse (30310231123), we get a palindrome (62423432426).

The spelling of 32113201303 in words is "thirty-two billion, one hundred thirteen million, two hundred one thousand, three hundred three".

Divisors: 1 61 8423 62501 513803 3812561 526445923 32113201303