32120314000133 has 8 divisors (see below), whose sum is σ = 32140140537120. Its totient is φ = 32100488162640.

The previous prime is 32120314000063. The next prime is 32120314000171. The reversal of 32120314000133 is 33100041302123.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-32120314000133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 32120314000099 and 32120314000108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32120314000633) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 114932978 + ... + 115212108.

It is an arithmetic number, because the mean of its divisors is an integer number (4017517567140).

Almost surely, 2^{32120314000133} is an apocalyptic number.

It is an amenable number.

32120314000133 is a deficient number, since it is larger than the sum of its proper divisors (19826536987).

32120314000133 is a wasteful number, since it uses less digits than its factorization.

32120314000133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 349747.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 32120314000133 its reverse (33100041302123), we get a palindrome (65220355302256).

The spelling of 32120314000133 in words is "thirty-two trillion, one hundred twenty billion, three hundred fourteen million, one hundred thirty-three", and thus it is an aban number.