32121040133131 has 4 divisors (see below), whose sum is σ = 32121128257000. Its totient is φ = 32120952009264.

The previous prime is 32121040133129. The next prime is 32121040133249. The reversal of 32121040133131 is 13133104012123.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 32121040133131 - 2¹ = 32121040133129 is a prime.

It is a super-2 number, since 2×32121040133131² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 32121040133096 and 32121040133105.

It is not an unprimeable number, because it can be changed into a prime (32121040130131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43512906 + ... + 44244943.

It is an arithmetic number, because the mean of its divisors is an integer number (8030282064250).

Almost surely, 2^{32121040133131} is an apocalyptic number.

32121040133131 is a deficient number, since it is larger than the sum of its proper divisors (88123869).

32121040133131 is an equidigital number, since it uses as much as digits as its factorization.

32121040133131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 88123868.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 32121040133131 its reverse (13133104012123), we get a palindrome (45254144145254).

The spelling of 32121040133131 in words is "thirty-two trillion, one hundred twenty-one billion, forty million, one hundred thirty-three thousand, one hundred thirty-one".