Base | Representation |
---|---|
bin | 1110100111000110110011… |
… | …11001100110100100000001 |
3 | 11012202121011201102022201102 |
4 | 13103203121321212210001 |
5 | 13202404230322130423 |
6 | 152200153501544145 |
7 | 6524213425306031 |
oct | 723433171464401 |
9 | 135677151368642 |
10 | 32130011130113 |
11 | a268296723206 |
12 | 372b017875055 |
13 | 14c0b01c741c0 |
14 | 7d115a9a18c1 |
15 | 3aab96ab7c28 |
hex | 1d38d9e66901 |
32130011130113 has 32 divisors (see below), whose sum is σ = 35353127255040. Its totient is φ = 29021879577600.
The previous prime is 32130011130083. The next prime is 32130011130127. The reversal of 32130011130113 is 31103111003123.
It is a de Polignac number, because none of the positive numbers 2k-32130011130113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32130011130143) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 66909095 + ... + 67387587.
It is an arithmetic number, because the mean of its divisors is an integer number (1104785226720).
Almost surely, 232130011130113 is an apocalyptic number.
It is an amenable number.
32130011130113 is a deficient number, since it is larger than the sum of its proper divisors (3223116124927).
32130011130113 is a wasteful number, since it uses less digits than its factorization.
32130011130113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 479169.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 32130011130113 its reverse (31103111003123), we get a palindrome (63233122133236).
The spelling of 32130011130113 in words is "thirty-two trillion, one hundred thirty billion, eleven million, one hundred thirty thousand, one hundred thirteen".
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