Base | Representation |
---|---|
bin | 11101111011000110… |
… | …010001011110111010 |
3 | 10001221012021210001201 |
4 | 131323012101132322 |
5 | 1011300240404424 |
6 | 22432121404414 |
7 | 2215132414423 |
oct | 357306213672 |
9 | 101835253051 |
10 | 32130013114 |
11 | 12698611451 |
12 | 628833970a |
13 | 3050760ba4 |
14 | 17ab2a864a |
15 | c80b1dd44 |
hex | 77b1917ba |
32130013114 has 8 divisors (see below), whose sum is σ = 48372861888. Its totient is φ = 16005725820.
The previous prime is 32130013109. The next prime is 32130013193. The reversal of 32130013114 is 41131003123.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 32130013091 and 32130013100.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29639692 + ... + 29640775.
It is an arithmetic number, because the mean of its divisors is an integer number (6046607736).
Almost surely, 232130013114 is an apocalyptic number.
32130013114 is a deficient number, since it is larger than the sum of its proper divisors (16242848774).
32130013114 is a wasteful number, since it uses less digits than its factorization.
32130013114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 59280740.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 32130013114 its reverse (41131003123), we get a palindrome (73261016237).
Subtracting 32130013114 from its reverse (41131003123), we obtain a palindrome (9000990009).
The spelling of 32130013114 in words is "thirty-two billion, one hundred thirty million, thirteen thousand, one hundred fourteen".
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