Base | Representation |
---|---|
bin | 11101111011000110… |
… | …010101111100111001 |
3 | 10001221012022201011121 |
4 | 131323012111330321 |
5 | 1011300242001132 |
6 | 22432122025241 |
7 | 2215132521661 |
oct | 357306257471 |
9 | 101835281147 |
10 | 32130031417 |
11 | 12698624180 |
12 | 6288348221 |
13 | 3050769313 |
14 | 17ab2b11a1 |
15 | c80b24497 |
hex | 77b195f39 |
32130031417 has 4 divisors (see below), whose sum is σ = 35050943376. Its totient is φ = 29209119460.
The previous prime is 32130031411. The next prime is 32130031463. The reversal of 32130031417 is 71413003123.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32130031417 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 32130031391 and 32130031400.
It is not an unprimeable number, because it can be changed into a prime (32130031411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1460455963 + ... + 1460455984.
It is an arithmetic number, because the mean of its divisors is an integer number (8762735844).
Almost surely, 232130031417 is an apocalyptic number.
It is an amenable number.
32130031417 is a deficient number, since it is larger than the sum of its proper divisors (2920911959).
32130031417 is a wasteful number, since it uses less digits than its factorization.
32130031417 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2920911958.
The product of its (nonzero) digits is 1512, while the sum is 25.
The spelling of 32130031417 in words is "thirty-two billion, one hundred thirty million, thirty-one thousand, four hundred seventeen".
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