3213043414433 has 8 divisors (see below), whose sum is σ = 3281919949440. Its totient is φ = 3144188292400.

The previous prime is 3213043414417. The next prime is 3213043414459. The reversal of 3213043414433 is 3344143403123.

3213043414433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3213043414433 - 2⁴ = 3213043414417 is a prime.

It is a super-2 number, since 2×3213043414433² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3213043414393 and 3213043414402.

It is not an unprimeable number, because it can be changed into a prime (3213043417433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5049743 + ... + 5650308.

It is an arithmetic number, because the mean of its divisors is an integer number (410239993680).

Almost surely, 2^{3213043414433} is an apocalyptic number.

It is an amenable number.

3213043414433 is a deficient number, since it is larger than the sum of its proper divisors (68876535007).

3213043414433 is a wasteful number, since it uses less digits than its factorization.

3213043414433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10706487.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 3213043414433 its reverse (3344143403123), we get a palindrome (6557186817556).

The spelling of 3213043414433 in words is "three trillion, two hundred thirteen billion, forty-three million, four hundred fourteen thousand, four hundred thirty-three".